the weight normal to the slope is mgcosTheta.
friction then is mu*mgCosTheta
A 4422.0 kg truck is parked on a 10.8° slope. What is the friction force on the truck?
4 answers
3446.4
Cry
one of the links have the answer
q.gs/D2Tva
q.gs/D2Tvb
q.gs/D2Tvc
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q.gs/D2Tve
q.gs/D2Tvf
q.gs/D2Tvg
q.gs/D2Tva
q.gs/D2Tvb
q.gs/D2Tvc
q.gs/D2Tvd
q.gs/D2Tve
q.gs/D2Tvf
q.gs/D2Tvg