Asked by Maxx
How do i find the asymptotes?
y=(1/x-4)+3
y=(1/x-4)+3
Answers
Answered by
Steve
vertical asymptotes where the denominator is zero.
To find horizontal asymptotes, find y when x gets really huge. Remember that
1/∞ = 0
∞-4 = ∞
To find horizontal asymptotes, find y when x gets really huge. Remember that
1/∞ = 0
∞-4 = ∞
Answered by
Maxx
So an asymptote would be X=2.75
Answered by
Steve
heavens! How did you get that?
y = 1/(x-4) + 3
x-4=0 when x=4
So, there is a vertical asymptote at x=4
Now, what happens when x->∞?
1/(x-4) -> 1/∞ -> 0
So, y=0+3 = 3
is a horizontal asymptote
See the graph at
http://www.wolframalpha.com/input/?i=1%2F%28x-4%29+%2B+3
y = 1/(x-4) + 3
x-4=0 when x=4
So, there is a vertical asymptote at x=4
Now, what happens when x->∞?
1/(x-4) -> 1/∞ -> 0
So, y=0+3 = 3
is a horizontal asymptote
See the graph at
http://www.wolframalpha.com/input/?i=1%2F%28x-4%29+%2B+3
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