Asked by John
Find an expression for dy/dx
y^3+(1/y)=x^2-7y
y^3+(1/y)=x^2-7y
Answers
Answered by
Damon
3 y^2 dy/dx - dy/dx / y^2 = 2 x -7 dy/dx
dy/dx (3 y^2 -1/y^2 + 7) = 2 x
dy/dx = 2 x /[ 3 y^2 -y^-2 + 7 ]
dy/dx (3 y^2 -1/y^2 + 7) = 2 x
dy/dx = 2 x /[ 3 y^2 -y^-2 + 7 ]
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