Asked by Sunil
                A floor which measures 15m*8m is to be laid with tiles measuring 50cm by 25 cm. Find the number of tiles required. Further, if a carpet is laid on the floor so that a space of 1m exists between its edges and the edges of the floor, what fraction of the floor is uncovered?
            
            
        Answers
                    Answered by
            Reiny
            
    area of floor = 120 m^2
area of one tile = .5*.25 or .125 m^2
number of tiles = 120/.125 = 960
or
we need 30 tiles along one wall, and 32 along the other wall, so 30*32 or 960 tiles
carpet is 13 by 6 or 78 m^2, leaving
120-78 or 42 m^2 of the floor exposed
    
area of one tile = .5*.25 or .125 m^2
number of tiles = 120/.125 = 960
or
we need 30 tiles along one wall, and 32 along the other wall, so 30*32 or 960 tiles
carpet is 13 by 6 or 78 m^2, leaving
120-78 or 42 m^2 of the floor exposed
                    Answered by
            Antra
            
    In my book the answer is 960, 7upon 20😩 
    
                    Answered by
            Tanvi
            
    But in my book answer is 960 tiles right but 1 upon 2
    
                    Answered by
            Tia 
            
    In my book the answer is 960 for the tiles 
    
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