Question
if 9560 J of energy were absorbed by 25.0g of ice at 0 degrees Celsius what would be the final temperature? First you must calculate the energy required to melt ice completely. With the remaining energy (Q).
This is the equation i came up with but i'm not even sure if its the right equation.
Q= (s)(m)(T).
This is the equation i came up with but i'm not even sure if its the right equation.
Q= (s)(m)(T).
Answers
bobpursley
No.
9650=.025*Hf + .025cwater(Tf-0)
heat=heatmeltingice+heatwater.
Look up the heat of fusion (J/kg) for water, and then the specific heat of water (J/kgK)
9650=.025*Hf + .025cwater(Tf-0)
heat=heatmeltingice+heatwater.
Look up the heat of fusion (J/kg) for water, and then the specific heat of water (J/kgK)