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A boxcar of mass 3.21 x 10^4 kg is rolling south at 5.16 m/s when it collides and couples with another boxcar of mass 5.18 x 10...Asked by lizbeth
A boxcar of mass 3.21 x 10^4 kg is rolling south at 5.16 m/s when it collides and couples with another boxcar of mass 5.18 x 10^4 kg that is rolling north at 2.38 m/s. What is the velocity of the coupled boxcars after collision? Take north as positive and express your result to three significant digits.
Please help!
Please help!
Answers
Answered by
bobpursley
conservation of momentum
3.21E4(-5.16)+5.18E4(2.38)=(summasses) V
solve for V
3.21E4(-5.16)+5.18E4(2.38)=(summasses) V
solve for V
Answered by
lizbeth
-.505
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