Asked by Will
the length of a rectangle is 4cm more than the width of the rectangle. If you increase the length by 8cm and decrease the width by 4cm, the area will remained unchanged. Find the original dimensions
Answers
Answered by
bobpursley
(L-4)L=area=(L+8)(w-4)
(L-4)L=(L+8)(L-4-4)
L^2-4L=L^2-8L +8L-64 check that.
-4L=-64
solve for l, then W
(L-4)L=(L+8)(L-4-4)
L^2-4L=L^2-8L +8L-64 check that.
-4L=-64
solve for l, then W
Answered by
Reiny
old width ----x
old length --- x+4
new width --- x-4
new length --- x+4 +8 =x + 12
x(x+4) = (x-4)(x+12)
x^2 + 4x = x^2 + 8x - 48
-4x = -48
x = 12
<b>old rectangle is 12 by 16
for an area of 192</b>
new rectangle is 8 by 24
for an area of 192
My answer is correct
old length --- x+4
new width --- x-4
new length --- x+4 +8 =x + 12
x(x+4) = (x-4)(x+12)
x^2 + 4x = x^2 + 8x - 48
-4x = -48
x = 12
<b>old rectangle is 12 by 16
for an area of 192</b>
new rectangle is 8 by 24
for an area of 192
My answer is correct
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