Asked by Henry
Pumping stations deliver gasoline at the rate modeled by the function D, given by D(t)= 6t/(1+2t) with t measure in hours and and R(t) measured in gallons per hour. How much oil will the pumping stations deliver during the 3-hour period from t = 0 to t = 3? Give 3 decimal places.
I'm pretty sure you don't plug in 3 to the equation so I am wondering what you do do.
I'm pretty sure you don't plug in 3 to the equation so I am wondering what you do do.
Answers
Answered by
Steve
gallons = rate * time, so you get
∫[0,3] D(t) dt
= ∫[0,3] 6t/(1+2t) dt
= 9 - (3log7)/2
= 6.0811
∫[0,3] D(t) dt
= ∫[0,3] 6t/(1+2t) dt
= 9 - (3log7)/2
= 6.0811
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