Asked by Boberto

At what pressure would 0.150 mole of nitrogen gas at -23.0oC occupy 8.90 L?

-23.o0c = 250 K

P=(0.150 mol)(8.31 KPA x L/ K x mol)(250 K) = P

is this right?
Answered by Boberto
I know what to do in this question. My teacher showed me.