Asked by Boberto
At what pressure would 0.150 mole of nitrogen gas at -23.0oC occupy 8.90 L?
-23.o0c = 250 K
P=(0.150 mol)(8.31 KPA x L/ K x mol)(250 K) = P
is this right?
-23.o0c = 250 K
P=(0.150 mol)(8.31 KPA x L/ K x mol)(250 K) = P
is this right?
Answers
Answered by
Boberto
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