Question
The diagonal of a TV set is 26 inches long. Its length is 14 inches more than the height. Find the dimensions of the TV set.
Answers
Reiny
height ---- x
length ---- x+14
x^2 + (x+14)^2 = 26^2
2x^2 + 28x + 196 = 676
x^2 + 14x = 240
completing the square ...
x^2 + 14x + 49 = 240+49
(x+7)^2 = 289
x+7 = √289 = 17
x = 10
the TV is 10 inches by 24 inches
(odd size)
check:
10^2 + 24^2
= 100 + 576
= 676
= 26^2
My answer is correct
length ---- x+14
x^2 + (x+14)^2 = 26^2
2x^2 + 28x + 196 = 676
x^2 + 14x = 240
completing the square ...
x^2 + 14x + 49 = 240+49
(x+7)^2 = 289
x+7 = √289 = 17
x = 10
the TV is 10 inches by 24 inches
(odd size)
check:
10^2 + 24^2
= 100 + 576
= 676
= 26^2
My answer is correct
aj
13