Asked by Brad
The volume of a right circular cylinder (think of a pop can) is jointly proportional to the square of the radius of the circular base and to the height. For example, when the height is 10.62 cm and the radius is 3 cm, then the volume is 300 cm3.
Find the formula of the volume of a cylinder using the following variables: V = volume, h = height, r = radius. Describe how you found the constant in the formula you have given.
Using the formula you just discovered, find the volume to the nearest tenth of a cylinder with radius 4 cm and height 15.92 cm
Find the formula of the volume of a cylinder using the following variables: V = volume, h = height, r = radius. Describe how you found the constant in the formula you have given.
Using the formula you just discovered, find the volume to the nearest tenth of a cylinder with radius 4 cm and height 15.92 cm
Answers
Answered by
Damon
Oh well, I'll play
300 = k * 3^2 * 10.62
so
k = 300/(9*10.62) = 3.14
remarkable :)
in fact v = pi r^2 h
= pi * 3^2 * 10.62
= 300.27 :)
so we say
v = 3.14 * r^2 *h
= 3.14 * 16 * 15.92
=785 cm^3
300 = k * 3^2 * 10.62
so
k = 300/(9*10.62) = 3.14
remarkable :)
in fact v = pi r^2 h
= pi * 3^2 * 10.62
= 300.27 :)
so we say
v = 3.14 * r^2 *h
= 3.14 * 16 * 15.92
=785 cm^3
Answered by
Anonymous
An open top box with a square base is to be constructed from two types of materials,one for the bottom and one for the sides. The volume of the box is to be a cubic feet. The cost of the bottom is php 4 per square, foot and the cost of material for the side is php 3 per square foot.Let be the length of the edge of the square base and let y be the height of the open box
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