Question

Two students each hit a golf ball at the same speed, but the first student hits his ball at an angle of 60.34o with the horizontal, and the second student hits his at (30-0.34)o with the horizontal. Which ball goes further? Which one hits the ground first? (Neglect air resistance.)

Answer 1

Xo = Cos60.34 = 0.4949
Yo = sin60.34 = 0.8690

Answer 2

Oops!! Please disregard my first post.

First Student:
Xo = Cos60.34 = 0.4949
Yo = sin60.34 = 0.8690

Y = Yo + g*Tr = 0, Tr = -Yo/g = -0.8690/-9.8 = 0.0887 s. = Rise time. Tf = Tr = 0.0887 s.

T = Tr+Tf = 0.0887 + 0.0887 = 0.1774 s. = Time in air.

Dx = Xo*T = 0.4949 * 0.1774 = 0.0878

2nd Student:
Repeat the above calculations for
the 2nd student and compare.

Answer 3

2nd student