Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Determine the pH of the following solutions. 1) 0.600 M HCl 2) 0.052 moles of H2SO4 dissolved in 4.2 L of water. 3)5.6 grams HN...Asked by Tyra
Determine the pH of the following solutions.
1) 0.600 M HCl
2) 0.052 moles of H2SO4 dissolved in 4.2 L of water.
3)5.6 grams HNO3 dissolved in 450 ml of water.
4) 2.5 grams of NaOH dissolved in 500 mL of water.
5) adding 2 grams NaH dissolved in 0.56 L of water.
6) 20 mL of 0.27 M HNO3 is diluted to 500 mL.
1) 0.600 M HCl
2) 0.052 moles of H2SO4 dissolved in 4.2 L of water.
3)5.6 grams HNO3 dissolved in 450 ml of water.
4) 2.5 grams of NaOH dissolved in 500 mL of water.
5) adding 2 grams NaH dissolved in 0.56 L of water.
6) 20 mL of 0.27 M HNO3 is diluted to 500 mL.
Answers
Answered by
DrBob222
Tyra, you really need to help by answering the questions we ask. I need to know WHAT you don't understand about a problem.
1. For strong acids like HCl which ionize 100%, then pH = -log HCl)
3. Convert 5.6 g to mols. mols = grams/molar mass. Then the definition of molarity is M = mols/L. You know mols from the conversion you made from 5.6 grams and you know it is in 0.450 L.
4. is the same procedure as 3.
6. For dilutions use the dilution formula of
mL1 x M1 = mL2 x M2
20 x 0.27 = 500 x ?
Solve for ?
1. For strong acids like HCl which ionize 100%, then pH = -log HCl)
3. Convert 5.6 g to mols. mols = grams/molar mass. Then the definition of molarity is M = mols/L. You know mols from the conversion you made from 5.6 grams and you know it is in 0.450 L.
4. is the same procedure as 3.
6. For dilutions use the dilution formula of
mL1 x M1 = mL2 x M2
20 x 0.27 = 500 x ?
Solve for ?
Answered by
Sly
0.0108
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.