Asked by jewellry
2. Write an equation in slope-intercept form of a line with the given parametric equations.
x = 9t + 2
y = 2t – 2
answer choices:
a)y=(2/9)x - (22/9)
b)y=(22/9)x + (2/9)
c) y=(9/2)x - (9/22)
d) y=(2/5)x + (2/3)
If you could show some work, because I'm pretty confused. Thank you :)
x = 9t + 2
y = 2t – 2
answer choices:
a)y=(2/9)x - (22/9)
b)y=(22/9)x + (2/9)
c) y=(9/2)x - (9/22)
d) y=(2/5)x + (2/3)
If you could show some work, because I'm pretty confused. Thank you :)
Answers
Answered by
Reiny
solve each for t
x = 9t+2
9t = x-2
t = (x-2)/9
y = 2t-2
2t = y+2
t = (y+2)/2
so (x-2)/9 = (y+2/2
cross-multiply
2x - 4 = 9y + 18
2x - 9y = 22--> I would have like that from
-9y = -2x + 22
y = (2/9)x - 22/9 -- looks like the a)'s have it.
x = 9t+2
9t = x-2
t = (x-2)/9
y = 2t-2
2t = y+2
t = (y+2)/2
so (x-2)/9 = (y+2/2
cross-multiply
2x - 4 = 9y + 18
2x - 9y = 22--> I would have like that from
-9y = -2x + 22
y = (2/9)x - 22/9 -- looks like the a)'s have it.
Answered by
jewellry
Wow, Thank you so much Reiny!!
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