Question

If h(x) = the square root of 4 + 3f(x)
where f(2) = 4 and f '(2) = 2, find h'(2).

i got the derivative as 1/2(4+3f(x))^-1/2

then i solved for the inside which is (0+3(8))
then multiplied the the two eating and i got 3.... but answer is wrong =(

Answer 1

h = √(4+3f)
h' = 3/(2√(4+3f)) f'

at x=2,
dh/dx = 3/(2√(4+12)) (2) = 6/8 = 3/4