Asked by Linda
there are 8 opposite sex married couples at a party. two people are chosen at random to win a door prize.
A. what is the probability that the 2 people will be married to each other?
B. what is the probability that the 2 people will be same sex?
C. if 6 people are chosen whats the probability that they are 3 married couples?
A. what is the probability that the 2 people will be married to each other?
B. what is the probability that the 2 people will be same sex?
C. if 6 people are chosen whats the probability that they are 3 married couples?
Answers
Answered by
Reiny
a) the number of ways to choose 2 out of the 16 people is C16,2) = 120
there are 8 couples married to each other, so the prob is 8/120 = 1/15
b) the number of ways that the two chosen are different is C(8,1)xC(8,1) = 64
so the number of ways that they are the same is 120-64 = 56
so prob they are the same sex = 56/120 = 7/15
Now you try c) and explain your reasoning to us
("opposite sex married couples", wouldn't Sarah Palin be proud of that textbook author, lol)
there are 8 couples married to each other, so the prob is 8/120 = 1/15
b) the number of ways that the two chosen are different is C(8,1)xC(8,1) = 64
so the number of ways that they are the same is 120-64 = 56
so prob they are the same sex = 56/120 = 7/15
Now you try c) and explain your reasoning to us
("opposite sex married couples", wouldn't Sarah Palin be proud of that textbook author, lol)
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