momentum is conserved
71 * 2.5 = 59 * v
the direction is negative x
What's the other's velocity?
71 * 2.5 = 59 * v
the direction is negative x
The momentum of a skater can be calculated by multiplying its mass by its velocity. Let's assume the velocity of the other skater is v.
Before the push-off:
The momentum of the 71 kg skater = (Mass of 71 kg skater) × (Velocity of 71 kg skater)
The momentum of the other skater = (Mass of other skater) × (Velocity of other skater)
After the push-off:
The momentum of the 71 kg skater = (Mass of 71 kg skater) × (Final velocity of 71 kg skater)
The momentum of the other skater = (Mass of other skater) × (Final velocity of other skater)
Given:
Mass of 71 kg skater = 71 kg
Velocity of 71 kg skater = 2.5 m/s
To find the velocity of the other skater, we can set up the conservation of momentum equation:
(71 kg) × (2.5 m/s) + (59 kg) × (0 m/s) = (71 kg) × (Final velocity of 71 kg skater) + (59 kg) × (Final velocity of other skater)
Simplifying the equation:
177.5 kg·m/s = (71 kg) × (Final velocity of 71 kg skater) + (59 kg) × (Final velocity of other skater)
Since the initial velocity of the other skater is 0 m/s, we know that the initial momentum of the other skater is 0. This means we can simplify the equation further:
177.5 kg·m/s = (71 kg) × (Final velocity of 71 kg skater) + 0
Now we can solve for the final velocity of the other skater:
Final velocity of other skater = (177.5 kg·m/s) / (59 kg)
Calculating this:
Final velocity of other skater = 3 m/s
Therefore, the velocity of the other skater is 3 m/s in the positive x-direction.