Question

Electrons in a narrow beam travelling at a steady speed of 5 x 10^7 ms^-1 are directed into the space between two oppositely charged parallel plates 50mm apart. The potential difference between the plates is 2500V. The initial direction of the beam is parallel to the plates. Calculate:

The speed and direction of the electrons on leaving the plates.

(The force on each electron between the plates is 8 x 10^-15N and the time each electron spends between the plates if the plates are each 100mm in length is 2 Nanoseconds).

Answer 1

ummm. No.
The force on the electrons is Eq= 2500*1.6e-19 = 4e-16.
x direction: v is constant, i.e. 5e7
y direction: v=at = Ft/m = 4e-16*2e-9/m (sorry don't know the mass of an electron offhand).
Then Pythagorean to find total v and tan-1 to find angle.