Question

How many grams of salt can be produced from five grams of sodium and unlimited bromine?

Is this 39.75 g NaBr?

Answer 1

5 grams of Na is 5/23 = .2174 mols

so we get .2174 mols of NaBr

NaBr = 23 + 80 = 103 grams/mol

.2174 * 103 = 22.4 grams