Asked by Jason L
A survey of community banks asked about the loan to deposit ratio (LTDR) a banks total loans as a percent of its total deposits. The mean LTDR for the 110 banks in the sample is xbar = 76.7 and the standard deviation is s = 12.3. In the text a 95% confidence interval (using a z score) is given for the mean LTDR for community banks. This solution is theoretically not completely correct. What should the interval be?
A -
74.6-79.2
74.38-79.02
74.3-78.9
74.28-78.88
74.2-78.8
Formula:
CI95 = mean + or - 1.96(sd divided by √n)
...where + or - 1.96 represents the 95% confidence interval using a z-table, sd = standard deviation, √ = square root, and n = sample size.
With your data:
CI95 = 76.7 + or - 1.96(12.3/√110)
Finish the calculation for your interval.
A -
74.6-79.2
74.38-79.02
74.3-78.9
74.28-78.88
74.2-78.8
Formula:
CI95 = mean + or - 1.96(sd divided by √n)
...where + or - 1.96 represents the 95% confidence interval using a z-table, sd = standard deviation, √ = square root, and n = sample size.
With your data:
CI95 = 76.7 + or - 1.96(12.3/√110)
Finish the calculation for your interval.
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.