A hoop starts from rest at a height 1.8 m above the base of an inclined plane and rolls down under the influence of gravity. What is the linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface? (Neglect friction.)

I don't know what equation to use, other equations online don't define the variables.

2 answers

gravitational potential energy is converted to kinetic energy

m g h = 1/2 m v²

9.8 * 1.8 = v² / 2
Thank You this is what i needed