hi! so I have a rational equation : y = -3/x+1 and i'm wondering how you find the horizontal and vertical asymptotes.

Answer 1

do you mean
y = -3/(x+1)

or what you typed?

Answer 2

oh, its what I typed :)

Answer 3

y = -3/(x+1)
Vertical Asymptotes :x=−1
Horizontal Asymptotes :y=0
No Oblique Asymptotes
Hoped that helped :)

Answer 4

yes, thank you but just one question: how did you know that y=0? I get where the x comes from but not the y :(

Answer 5

ok
if it is

y = -(3/x) + 1

then clearly when x -->0 this becomes huge positive or negative depending on if x is positive or negative. That is the poit of vertical asymptotes

as x becomes huge positive or negative, y---> 1 horizontal

Answer 6

Amma said to do what she typed, y = -3/x + 1

Answer 7

OH, i must of typed it wrong; Sorry about that!
Vertical Asymptotes :x=0
Horizontal Asymptotes :y=1
No Oblique Asymptotes
So, what Damon said :)