Asked by lucky
Constuct a triangle ABC ,given that angleA is 70 degree & angle C is 35 degree and length of perpendicular from A on BC is 5cm .meausre BC
Answers
Answered by
Steve
Since A+B+C=180, angle B is 75°
BC = 5/sin75°
As for the construction,
draw a horizontal line AP
Construct angle A, labeling Q the end of the other ray than AP.
Construct a line XY parallel to AP, 5 units above it.
If necessary, extend AQ so it intersects XY at C.
Now construct angle C.
Point B is the intersection of that new ray with AP.
BC = 5/sin75°
As for the construction,
draw a horizontal line AP
Construct angle A, labeling Q the end of the other ray than AP.
Construct a line XY parallel to AP, 5 units above it.
If necessary, extend AQ so it intersects XY at C.
Now construct angle C.
Point B is the intersection of that new ray with AP.
Answered by
tsetse
Sin A over a equels to sin B over b
Sin 70 over 5 equals to sin 75 over b
We cross multiply
bsin70 =5sin75
We divide by sin70
b=5sin75
sin70
b=5,14cm
Sin 70 over 5 equals to sin 75 over b
We cross multiply
bsin70 =5sin75
We divide by sin70
b=5sin75
sin70
b=5,14cm
Answered by
Himanshu verma
I am not under stand
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