Question
Given a population mean IQ =100 and a standard deviation of 16, for a random sample of size 64, what is the probability that the sample mean IQ will be greater than 104?
Answers
PsyDAG
Z = (sample mean-pop.mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.