Question

joules needed to melt 30.0 g of ice at 0 ∘C and to warm the liquid to 60.0 ∘C

so i did Q=mFf which i set up like
30.g x 334 j/c = 10020 J

then i'm sorta confused what i'm doing next. explain in detail please?

Answer 1

That melts the ice at zero to liquid water at zero C.
Now to heat it from zero C to 60 C is q = mc*delta T.
q = 30 x 4.184 x (Tfinal-Tinitial)
Then add the two for the total.