Asked by J
                joules needed to melt 30.0 g of ice at 0 ∘C and to warm the liquid to 60.0 ∘C
so i did Q=mFf which i set up like
30.g x 334 j/c = 10020 J
then i'm sorta confused what i'm doing next. explain in detail please?
            
        so i did Q=mFf which i set up like
30.g x 334 j/c = 10020 J
then i'm sorta confused what i'm doing next. explain in detail please?
Answers
                    Answered by
            DrBob222
            
    That melts the ice at zero to liquid water at zero C. 
Now to heat it from zero C to 60 C is q = mc*delta T.
q = 30 x 4.184 x (Tfinal-Tinitial)
Then add the two for the total.
    
Now to heat it from zero C to 60 C is q = mc*delta T.
q = 30 x 4.184 x (Tfinal-Tinitial)
Then add the two for the total.
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