Asked by Boberto

At what pressure would 0.150 mole of nitrogen gas at -23.0^o C occupy 8.90 L ?
Answered by bobpursley
P=nRT/V

change temp to kelvins
Answered by Boberto
thanks bob
Answered by Anonymous
P = nRT / V

P = [ (0.150 mol) (0.08206 L atm mol¯1 K¯1) (296.0 K) ] / 8.90 L