Asked by Boberto

At what pressure would 0.150 mole of nitrogen gas at -23.0^o C occupy 8.90 L ?

9 years ago

Answered by bobpursley

P=nRT/V

change temp to kelvins

9 years ago

Answered by Boberto

thanks bob

9 years ago

Answered by Anonymous

P = nRT / V

P = [ (0.150 mol) (0.08206 L atm mol¯1 K¯1) (296.0 K) ] / 8.90 L

9 years ago

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