Asked by Homework
Determine graphically the equilibrant of two forces of 15N and 20N if the angle between them is 135degrees
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Answered by
Henry
F1 = 15N[0o], F2 = 20N[135o].
F1+F2 = 15 + -14.1+14.1i = 0.9 + 14.1i = 14.2 N.[86.4o] = 0.89 + 14.18i
F3 must be equal to F1+F2 in magnitude and 180o out of phase:
F3 = 14.2N[86.4+180] = 14.2[266.4o].= 14.2[86.4o] S. of W. = -0.89 - 14.18i
F1+F2 = 15 + -14.1+14.1i = 0.9 + 14.1i = 14.2 N.[86.4o] = 0.89 + 14.18i
F3 must be equal to F1+F2 in magnitude and 180o out of phase:
F3 = 14.2N[86.4+180] = 14.2[266.4o].= 14.2[86.4o] S. of W. = -0.89 - 14.18i
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