2Al + 6HBr ==> 2AlBr3 + 3H2
4 mols Al will produce how much H2? That's 4 mols Al x (3 mols H2/2) mols Al) = ?
3 mols HBr will produce how much H2?That's 3 mols HBr x (3 mols H2/6 mols HBr) = ?
This is a limiting reagent problem. The answer to how much is produced is ALWAYS the smaller value of the two possibilities.
Consider the following reaction: Al + HBr ---> AlBr3 + H2 . When 4 moles of Al reacts with 3 moles of HBr, how many moles of H2 are formed?
1 answer