Ask a New Question

Asked by Henry

The region bounded by y=3/(1+x^2), y=0, x=0 and x=3 is rotated about the line x=3. Using cylindrical shells, set up an integral for the volume of the resulting solid. The limits of integration are:
9 years ago

Answers

Answered by Steve
v = ∫[0,3] 2πrh dx
where r=3-x and h=3/(1+x^2)

or, using discs,

v = ∫[0,3] π(R^2-r^2) dy
where R=3 and r=3-√(3/y - 1)
9 years ago
Answered by You
nice
3 years ago

Related Questions

Consider the region bounded by the graphs of the equations x=y^2 and y=3x. Set up 2 integrals, one... The region bounded by y=2.5x^2 and y=4x is to be rotated about both axes and the volume generated ca... Let R be the region bounded by y=6sin((pi/2)x), y=6(x-2)^2, y=3x+3 containing the point (2,6). Find... Let R be the region bounded by y=e^x, y=2. and the y-axis. Find the volume of the solid obtained by... The region bounded by y = x^2 and y = 4 is rotated about the line y = -1. The volume of the solid g... The region bounded by y=x^2 and y=4 is rotated about the line y=-1. Find the volume. The region R bounded by y=e^-x and y=0 and lying to the right x=0 is rotated about the y-axis Let 𝑅 be the region bounded by the four straight lines 𝑦=𝑥, 𝑥+𝑦=4, 𝑦=𝑥−2 and 𝑥+ 𝑦 = 2. Find the sur... R is the region bounded above by the graph of f(x)=2e^−x^2 and below by the x-axis over the interval...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use