Asked by Josh
A 600W flashlamp fitted to a camera is operated by discharging a 10 000 uF capacitor through the lamp. The capacitor is charged initially from a 6V battery.
Calculate
A) the energy stores in the capacitor when fully charged
B) the duration of the flash
Calculate
A) the energy stores in the capacitor when fully charged
B) the duration of the flash
Answers
Answered by
Scott
watts = volts * amps = amps^2 * Ω
600 W = 6 V * 100 A = 100^2 * Ω
A)energy = 1/2 * farads * (volts)^2
B)use C and R (Ω) to find the time constant of the circuit
the capacitor is 95% discharged after 3 time constants
600 W = 6 V * 100 A = 100^2 * Ω
A)energy = 1/2 * farads * (volts)^2
B)use C and R (Ω) to find the time constant of the circuit
the capacitor is 95% discharged after 3 time constants
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