Question

A 600W flashlamp fitted to a camera is operated by discharging a 10 000 uF capacitor through the lamp. The capacitor is charged initially from a 6V battery.

Calculate
A) the energy stores in the capacitor when fully charged
B) the duration of the flash

Answer 1

watts = volts * amps = amps^2 * Ω

600 W = 6 V * 100 A = 100^2 * Ω

A)energy = 1/2 * farads * (volts)^2

B)use C and R (Ω) to find the time constant of the circuit
the capacitor is 95% discharged after 3 time constants