Asked by Kadyn
Perform the operation and put in standard form.
(8+square root of-12)-(4+2square root of 3i)
(8+square root of-12)-(4+2square root of 3i)
Answers
Answered by
Reiny
translated into Math ....
(8+√-12)-(4+2√3 i)
= 8 + 2√3 i - 4 - 2√3 i
= 4
aside:
√-12
= (√-1)√12
= i √4 √3
= 2√3 i
(8+√-12)-(4+2√3 i)
= 8 + 2√3 i - 4 - 2√3 i
= 4
aside:
√-12
= (√-1)√12
= i √4 √3
= 2√3 i
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