Asked by Ri

Fnd the equation of the curve through the point (-1,2) of the differential equation dy/dx = -2xy/(x^2+1)
Answered by Steve
the solution to the d.e. is

y = c/(x^2+1)
c/2 = 2
c = 4

y = 4/(x^2+1)
Answered by Ri
@steve... i got c=2 log 2 .. before putting the pts i got the equation logy+log(1+x^2)=logc
Answered by Ri
@steve... now i further solved it... thnx.. ur answer is correct :) :)