If the dimension along the road is x, then we have a cost of
2.50x + 1.50x + 2*1.50y
= 4x + 3y = 270
The area is
a = xy = x(270-4x)/3
= 90x - 4/3 x^2
da/dx = 90 - 8/3 x
now you can find x and y for maximum area
a rectangular lot adjacent to a highway is to be enclosed by a fencing cost $ 2.50 per foot.along the highway $1.50 per foot on the other sides find the dimension of the largest lot that can be fenced off for $270.
Thank you God bless. Badly need it
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