Question
Justin has a total of 50 coins that are all nickels and quarters. He has 10 more nickels than quarters. How many of each coin does Justin have?
Answers
Bosnian
n = Number of nickels
q = Number of quarters
He has 10 more nickels than quarters mean :
n = q + 10
Justin has a total of 50 coins that are all nickels and quarters mean :
n + q = 50
n = q + 10 so :
n + q = 50
q + 10 + q = 50
2 q + 10 = 50 Subtract 10 to both sides
2 q + 10 - 10 = 50 - 10
2 q = 40 Divide both sides by 2
q = 40 / 2 = 20
n + q = 50
n + 20 = 50 Subtract 20 to both sides
n + 20 - 20 = 50 - 20 = 30
30 nickels and 20 quarters
q = Number of quarters
He has 10 more nickels than quarters mean :
n = q + 10
Justin has a total of 50 coins that are all nickels and quarters mean :
n + q = 50
n = q + 10 so :
n + q = 50
q + 10 + q = 50
2 q + 10 = 50 Subtract 10 to both sides
2 q + 10 - 10 = 50 - 10
2 q = 40 Divide both sides by 2
q = 40 / 2 = 20
n + q = 50
n + 20 = 50 Subtract 20 to both sides
n + 20 - 20 = 50 - 20 = 30
30 nickels and 20 quarters