write a single translation in algebraic notation for the following

(x,y) (x-6,y+2) followed by (x,y)
(x+3,y+1)

2 answers

the 2nd translation takes
(x-6,y+2) -> (x-6+3,y+2+1) = (x-3,y+3)
I read that as
(x,y) ---> (x-6,y+2)
followed by
(x,y) ---> (x+3, y + 1)

so:
(x,y) ---> (x-6,y+2) ---> (x-6 + 3,y+2 + 1)

or

(x,y) ----> (x-3, y+3)