x^2 - a^2 = x^2 - a^2
(x-a)^2 = x^2 - 2 a x + a^2
quite a different animal
is (x^2-a^2) the same as (x-a)^2. If so would (x^2-a^2)/x-a = x-a?
3 answers
(x^2-a^2)/(x-a)
= (x-a)(x+a) /(x-a)
= (x+a)
= (x-a)(x+a) /(x-a)
= (x+a)
what you are missing is a rule to remember
a^2-b^2 = (a+b)(a-b)
a^2-b^2 = (a+b)(a-b)