Asked by John
(〖3x〗^4/〖6x〗^3 )2
I'm having some trouble solving this. In the numerator is 3x to the 4th. In the denominator is 6x to the 3rd. All of that is in a bracket and it's all squared.
Do I have to first subtract the exponents, 4 - 3 and then multiply by the 2 exponent? I'm a little lost here.
Thank you.
I'm having some trouble solving this. In the numerator is 3x to the 4th. In the denominator is 6x to the 3rd. All of that is in a bracket and it's all squared.
Do I have to first subtract the exponents, 4 - 3 and then multiply by the 2 exponent? I'm a little lost here.
Thank you.
Answers
Answered by
Henry
The simplification process starts
inside the expression:
((3x)^4/(6x)^3)^2 =
(81x^4/216x^3)^2 = (3x/8)^2 = 9x^2/64.
inside the expression:
((3x)^4/(6x)^3)^2 =
(81x^4/216x^3)^2 = (3x/8)^2 = 9x^2/64.
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