Asked by Anonymous
A ball rolls off the edge of a tabletop and then lands on the floor 80 cm away from the base of the table. if the table is 1.20 high what is the initial velocity?
Answers
Answered by
bobpursley
time to fall 1.2 m:
h=4.8t^2=1.2
t= sqrt(1.2/4.8)
so velocity=.8m/time
h=4.8t^2=1.2
t= sqrt(1.2/4.8)
so velocity=.8m/time
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