Asked by Wayfinders
Calculate the mass of Na2C2O4 needed to react with 30mL of 0.050 M KMnO4.
The net ionic equation is:
2MnO4- + 5C2O4-2 + 16H+ —> 2Mn+2 + 10CO2 + 8H2O
I don't know where to start or how to end up with sodium oxalate.
Thanks!
The net ionic equation is:
2MnO4- + 5C2O4-2 + 16H+ —> 2Mn+2 + 10CO2 + 8H2O
I don't know where to start or how to end up with sodium oxalate.
Thanks!
Answers
Answered by
DrBob222
Step1. Calculate the mols KMnO4 used. mols KMnO4 = M x L = ?
Step2. Using the coefficients in the balanced equation, convert mols KMnO4 used to mols Na2C2O4 needed.
Step3. Then mass Na2C2O4 = mols Na2C2O4 x molar mass Na2C2O4.
Step2. Using the coefficients in the balanced equation, convert mols KMnO4 used to mols Na2C2O4 needed.
Step3. Then mass Na2C2O4 = mols Na2C2O4 x molar mass Na2C2O4.
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