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Two students are on a balcony 24.3 m above the street. One student throws a ball, b1, vertically downward at 15.8 m/s. At the s...Asked by Mariana
Two students are on a balcony 22 m above the street. One student throws a ball vertically downward at 15.5 m/s; at the same instant, the other student throws a ball vertically up- ward at the same speed. The second ball just misses the balcony on the way down.
How far apart are the balls 0.357 s after they are thrown? The acceleration of gravity is 9.8 m/s2 .
How far apart are the balls 0.357 s after they are thrown? The acceleration of gravity is 9.8 m/s2 .
Answers
Answered by
Chanz
x1 = 22 - 15.5(.357) - 4.9(.357^2)
x2 = 22 + 15.5(.357) - 4.9(.357^2)
Find the diff.
x2 = 22 + 15.5(.357) - 4.9(.357^2)
Find the diff.
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