Asked by Kaitlyn
How many moles of chlorate ions, zinc ions, and oxygen atoms are present in 0.433 mol of zinc chlorate?
Answers
Answered by
DrBob222
See your post on Al2(CO3)3 to see how to do this one.
Answered by
Ayanda
Znclo3>>>> zn^+2 +clo3^-1
Zn ions :znclo3
1 : 1
O.43moles : 0.433moles
Znclo3 :clo3 ions
1 : 1
0.433moles : 0.433 moles
Moles of znclo3 = (6.023*10^23)(0.433)
=2.607959 *10^23 molecules/atoms
Oxygen atoms in znclo3= 3*(2.607959*10^23)
=7.823877*10^23 atoms
Zn ions :znclo3
1 : 1
O.43moles : 0.433moles
Znclo3 :clo3 ions
1 : 1
0.433moles : 0.433 moles
Moles of znclo3 = (6.023*10^23)(0.433)
=2.607959 *10^23 molecules/atoms
Oxygen atoms in znclo3= 3*(2.607959*10^23)
=7.823877*10^23 atoms
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