Asked by Kaitlyn

How many moles of carbonate ions, aluminum ions, and oxygen atoms are present in 39.0 g aluminum carbonate?
Answered by DrBob222
39 g Al2(CO3)3
mols Al2(CO3)3 = grams/molar mass = ?
There are 2 mols Al^3+ for every mole of Al2(CO3)3
There 3 mols of [CO3]^2- for every mole of Al2(CO3)3.
There are 9 mols O atoms for every mole Al2(CO3)3
Answered by hi
hey guys my name is mike oxmaul
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