Asked by queenlatifah
a car moving at 10ms - was uniformly accelerated for 5s until it velocity reaches 20ms -. it then maintain the speed for another 20s after which the brakes were applied as the vehicle was finally brought to rest in a further 10s.draw the velocity time graph of the motion
Answers
Answered by
Damon
v at 10 m/s at t = 0
a = (final velocity-initial velocity)/time
= (20 - 10)/5 = 2 m/s^2
so from (0,10) slope up = 2 m/s^2
to (5,20)
from (5,20) to (25,20) horizontal
from (25,20) to (35, 0 ) straight slope down (slope = -2)
a = (final velocity-initial velocity)/time
= (20 - 10)/5 = 2 m/s^2
so from (0,10) slope up = 2 m/s^2
to (5,20)
from (5,20) to (25,20) horizontal
from (25,20) to (35, 0 ) straight slope down (slope = -2)
Answered by
Omotola
The acceleration, (final velocity-initial velocity)divided by time =10-30 divided by 5=-4
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.