Asked by Anonymous
A 69.6 kg fire fighter slides down a pole while a constant frictional force of 263 N retards his motion. A horizontal 18.7 kg platform is supported by a spring at the bottom of the pole to cushion the fall. The fire fighter starts from rest 5.80 m above the platform, and the spring constant is 2760 N/m. Calculate the fire fighter's speed just before he collides with the platform.
Answers
Answered by
bobpursley
mgh-energylostslidingpole =final energy
mg(5.8)-263*5.8=1/2 m vf^2
solve for vf
I don't see any connection with the mass of the platform, or spring holding it up.
mg(5.8)-263*5.8=1/2 m vf^2
solve for vf
I don't see any connection with the mass of the platform, or spring holding it up.
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