Asked by tommy
given a circle with (5,1) and (3,-1) as the endpoint of the diameter
Answers
Answered by
Reiny
centre is the midpoint of the diameter, so
(4,0)
equation: (x-4)^2 + y^2 = r^2
plug in (5,1) to find r^2
all done!
(4,0)
equation: (x-4)^2 + y^2 = r^2
plug in (5,1) to find r^2
all done!
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