Question

(sqr8) {(sqr9ab)/(sqr3b) + (sqr27a)}
How do you solve this

Answer 1

just multiply roots like anything else. If a square root contains a perfect square, like 16 or 49, you can factor the 4 or 7 out of the root. For this problem,

√8(√(9ab)/√(3b) + √(27a))
2√2 (√(9ab/3b) + 3√(3a))
2√2 (√(3a) + 3√(3a))
2√2 * 4√(3a)
8√(6a)

Answer 2

Is that

√8( √(9ab)/√(3b) + √(27a) )

or

√8 { √(9ab)/ [√(3b) + √(27a) ] }

furthermore, is it (√9)(ab) or √(9ab) ?
same for the other square roots .