Asked by Jay
The rate constant of a chemical equation has increased from 0.100s^-1 to 2.70s^-1 upon raising the temperature from 25C to 45C. Find the activation energy.
So far I done 3.30=(Ea/8.314)(-2.11x10^-4)
So far I done 3.30=(Ea/8.314)(-2.11x10^-4)