2nd:
t2 = 15/9.8
x2 = 1/2 (9.8) t2^2
1st:
t1 = t2+1.08
x1= 1/2(9.8)t1^2
Subtract x1-x2 to find out how far apart
A stone is dropped from the roof of a high building. A second stone is dropped 1.08s later. How far apart are the stone when the second one has reached a speed of 15.0?
1 answer
1 answer