Question
Three point charges are located away from a dot. charge 1 is 3 cm north of the dot and is 2.1 nC. Charge 2 is 5 cm east of the dot and is -5nC. Charge 3 is -10nC and is located 45 degrees northeast and 5.831 cm away from the dot. What is the net electric field at the position of the dot?
Answers
This is simple vector addition using kq/r^2 as the magnitude. The NE charge will need to be split into its components sin 45 and cos45 times the magnitude. And watch your signs, the N and NE have OPPOSITE signs and will act against each other.
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