Asked by Y
                Rochelle deposits $350 in an account that earns 6% annual interest, compounded quarterly. How much money will be in the account in 8 years? 
350(1.06)^32 =2258.685339
Can anyone check what I'm doing is correct or not?
Janet deposits %150 every month in an account that earns 6% interest, compounded monthly. How long will it tak Janet to save up $8000?
            
            
        350(1.06)^32 =2258.685339
Can anyone check what I'm doing is correct or not?
Janet deposits %150 every month in an account that earns 6% interest, compounded monthly. How long will it tak Janet to save up $8000?
Answers
                    Answered by
            Reiny
            
    no, since the 6% is compounded quarterly
you must divide .06 by 4
i = .06/4 = .015
so 350(1.015)^32
in the next one you would have to divide .06 by 12 to get i = .005
using the annuity formula
150( 1.005^n - 1)/.005 = 8000
(1.005^n -1)/.005 = 53.3333...
1.005^n - 1 = .26666...
1.005^n = 1.26666...
now we have to take logs and use the rules of logs
n log 1.005 = log 1.26666...
n = 47.396 months
= 3 years and appr 11 months
    
you must divide .06 by 4
i = .06/4 = .015
so 350(1.015)^32
in the next one you would have to divide .06 by 12 to get i = .005
using the annuity formula
150( 1.005^n - 1)/.005 = 8000
(1.005^n -1)/.005 = 53.3333...
1.005^n - 1 = .26666...
1.005^n = 1.26666...
now we have to take logs and use the rules of logs
n log 1.005 = log 1.26666...
n = 47.396 months
= 3 years and appr 11 months
                    Answered by
            Y
            
    Thanks for replying me, Reiny! 
I understand for the first one completely, but for the second one, did u use the annuity formula which is P[1-(1+r)^-n/r] ?? Because using (n-1) doesn't make sense to me..
    
I understand for the first one completely, but for the second one, did u use the annuity formula which is P[1-(1+r)^-n/r] ?? Because using (n-1) doesn't make sense to me..
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